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Reading Multiparm without replaced "#" in Python

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nd_sliu
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Hey!

I'm trying to get the unformatted multiparm parameter name from a hou.Parm object (my_multiparm_#_#). There might be an easy solution to do this but so far I'm having difficulty finding one..

Say I have a custom HDA with a string multiparm: my_string1, my_string2, my_string3. in Python, I can write:
my_hda_node = hou.node("/obj/geo1/my_hda")
for parm in my_hda_node.parms():
    print(parm.tuple().parmTemplate().name())

For my use case, I'd like to get:
"my_string#, my_string#, my_string#"
, rather than:
"my_string1, my_string2, my_string3"

But it appears in the documentation that we'll always get the "#" replaced. Additionally, there are nested multiparms with multiple pound signs, and I'd like to read those without the number replacements as well. Does anyone have any tips? Thanks!
Edited by nd_sliu - April 29, 2024 19:31:53
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kodra
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IiRC you can get the original name from ParmTemplate.
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nd_sliu
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@kodra. I believe that's what I'm doing here.
I tried parm.tuple().parmTemplate().name() and parm.parmTemplate().name()
both gives me something like my_string1 instead of my_string#

Afaik ParmTemplate describes the parameter as it is in the asset definition, so having it return the parameter name as if it's instanced feels confusing..
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kodra
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Well, sorry, I thought it'd work.

There is a working solution:

node = hou.node("../multiparm_test")
parmTuple = node.parmTuple("parm1_2_3")
indices = parmTuple.multiParmInstanceIndices()
name = parmTuple.name()

for i in range(len(indices)-1, -1, -1):
    index = indices[i]
    old_suffix = f"_{str(index)}" if i > 0 else str(index)
    name = name.removesuffix(old_suffix)

name += '_'.join(["#"] * len(indices))
    
print(name)

Might not be the most elegant snippet of code though.
Edited by kodra - May 1, 2024 02:41:26

Attachments:
multiparm_name.hip (89.7 KB)

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nd_sliu
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I thought so too! Thank you for the code snippet. Maybe this can be something for SideFX to dig into so the code can be a lot shorter.
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