Boolean with transitional fillet?

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Hey guys.

I'm having a lot of fun learning Houdini, doing all sorts of crazy things I wouldn't know how to do in other programs.

But I keep coming back to trying to figure out how to proceduraly make something like in the attachment.
It's just a tube being subtracted from a sphere, but the question is if there's a way to make the fillet/rounding/bevel where the transition happens in houdini?
Off course the Cookie node works great for booleans, but in a case like this a PolyBevel doesn't seem to cut it…
A way to adjust the transition with the Cookie node?

Thanks!
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Nothing seemed to happen with the animation… here's a couple of stills…



Edited by dubbilan - 2016年9月22日 13:56:11
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You may want to check out the Entagma video on Boolean Denting [entagma.com]. It is a different modeling approach to achieving that kind of look.
Using Houdini Indie 20.0
Windows 11 64GB Ryzen 16 core.
nVidia 3050RTX 8BG RAM.
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Thanks Enivob!

It's a really cool tutorial and technique, but I had tried out this VDB combine technique before. It doesn't really give me the control of the transition between the two volumes that I'm looking for, and also the shape remains quite bumpy and jagged due to cube nature of the voxels. Even at high resolutions it doesn't really look nice for what I'm looking for.
If I wanted to use the technique to design hard surface organic objects and use those for real-time use, I'm back to having to re-topologize, and then I might as well just model such stuff in Solid Works where I have the transition control that I'm looking for. Again, annoyingly needing to re-topologize and loosing the procedural tweakability after that…
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Yes, you can proceduraly bevel the result of a boolean. Make sure to output groups from the cookie sop, use those groups in the bevel sop. The high resolution your polygon objects the smaller your bevel has to be.

Attachments:
PorcBoolBevel.hiplc (54.9 KB)

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Thanks a lot Lyr!

It definitely goes in the right direction… still quite limiting how small the bevel has to be in this particular example, but maybe it's mathematically not_so_easy with polygons to go further.

In any case, this will work for many things, thanks
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