[solved] how to evaluate string attribute in delete node

Forums Houdini Indie and Apprentice [solved] how to evaluate string attribute in delete node

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oat: Member; 479 posts; Joined: Dec. 2009; Offline

Dec. 11, 2019 11:37 p.m.

The geometry has an attribute “id” which contains string values for each polygon.

How shall I refer to it in the “filter by expression” option in the delete node?

I tried the following, and they didn't seem to work:

@id = "Building A"
`@id` = "Building A"
@id == "Building A"
`@id` == "Building A"

Edited by oat - Dec. 13, 2019 00:50:06


CYTE: Member; 708 posts; Joined: Feb. 2017; Offline

Dec. 12, 2019 3:21 a.m.

Hey Oat,

one way is using a partition node and convert your id string to groups by typing id into the rule field. After that you can delete by group in the delete node.
But I guess there are other ways.

Cheers
CYTE


tamte: Member; 8780 posts; Joined: July 2007; Offline

Dec. 12, 2019 4:06 a.m.

in Delete SOP expression you may need to use this

strcmp(@id,"Building A")==0

however you can use Blast SOP instead and in Group parameter type:

@id="Building A"

Tomas Slancik
FX Supervisor
Method Studios, NY


oat: Member; 479 posts; Joined: Dec. 2009; Offline

Dec. 13, 2019 12:49 a.m.

Thank you, tamte. Both of your suggestions work like charms.

I'm glad that I learned a new trick from you.

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